BUILDERS TRAILS

BUILDERS OF TRAILSEvery year increases the number of syt and Palaces of pioneers, where the pipeline automodelismo. During the construction of trails is often necessary to perform smooth transitions from concentric circles to parallel straight, which causes some difficulties. At the station of young technicians of the Leningrad district of the city of Yerevan was built trendoriginal track. Today we decided to share our experience of graphical representation of the curves of the track.
There are five concentric circles with center at point “About1“, with different radii. The difference between the radii of 10 cm, a larger radius of 75 cm Distance between the five parallel lines M1H1, M2, N2, M3, N3, M4N4, M5N5 10 cm is Necessary to spend an additional 5 concentric arcs, the tangents to the circles parallel and straight.
 
To do this, you first need to line M3N3 down (or up, depending on the circuit of the track) to conduct a parallel auxiliary straight line at a distance equal to R3. A1 radius = 2*R3 is drawn the arc to the intersection with the auxiliary direct M6H6. The intersection point Of2 is the required centre for more concentric arcs. From the found center On2 of radius R1 hold for a tangent arc of a circle with radius and direct M5N5, radius R2 to the circle radius and direct M4N4 and so on, the last arc to hold the radius of a circle with radius R1 and straight line M1H1.
 
Required center O2 can be found and other builds. For example, a supporting line to hold to a straight M5N5 at a distance equal to R1. From the center O1 of radius equal to R1 + R5, draw an arc to the intersection of the additional line. The point of intersection is the same point O2.
 
The scheme of constructing curves of the track
Scheme for the construction of the curves of the track.
 
A. HAKOBYAN, Yerevan

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